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7v^2-36v=36
We move all terms to the left:
7v^2-36v-(36)=0
a = 7; b = -36; c = -36;
Δ = b2-4ac
Δ = -362-4·7·(-36)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-48}{2*7}=\frac{-12}{14} =-6/7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+48}{2*7}=\frac{84}{14} =6 $
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